(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2Y,其中x=-2,y=1/3

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(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2Y,其中x=-2,y=1/3
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(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2Y,其中x=-2,y=1/3
(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2Y,其中x=-2,y=1/3

(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2Y,其中x=-2,y=1/3
最后的Y是y吗?
如果是,原式化简后为-x^2,结果为-4

(x+y)x+(x-y)x-(6x^2y-2xy^2)除以(2y)
=2x^2-(3x^2-xy)
=xy-x^2
=(-2)*1/3-(-2)^2
=-14/3