作业帮(cosπ/8+sinπ/8)（cos^3π/8-sin^3π/8）
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(cosπ/8+sinπ/8)（cos^3π/8-sin^3π/8）
(cosπ/8+sinπ/8)（cos^3π/8-sin^3π/8）
(cosπ/8+sinπ/8)（cos^3π/8-sin^3π/8）
是要化简吗?
(cosπ/8+sinπ/8)(cos³3π/8-sin³3π/8)
=(cosπ/8+sinπ/8)(cosπ/8-sinπ/8)(cos²3π/8+cos3π/8sin3π/8+sin²3π/8)
=(cos²π/8-sin²π/8)(1+1/2sin3π/4)
=cosπ/4 × (1+1/2sin3π/4)
（老实说我觉得你应该知道cosπ/4和sin3π/4的值了……）
=cosπ/4 × （1+1/2sinπ/4）
=√2/2 × (1+√2/4)
=(2√2+1)/4
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
sinπ/8×cosπ/8
sinπ/8×cosπ/8
sinπ/8*cosπ/8
sinπ/8cosπ/8=( )
8sin(π/32)cos(π/32)cos(π/16)cos(π/8),求值
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8!急救急救
(cosπ/8+sinπ/8)（cos^3π/8-sin^3π/8）
(cosπ/8+sinπ/8)（cos^3π/8-sin^3π/8）.
(cos π/8+ sin π/8 ) (cos^3 π/8+sin^3 π/8 )的值.
cos 5π/8 cos π/8 + sin 5π/8 sin π/8=
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π)
cos^6(π/8)-sin^6(π/8)=求值,[cos^2(π/8)-sin^2(π/8)][cos^4(π/8)+sin^4(π/8)+cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-[sin^2(π/4)]/4]==7√2/16
cos(π/3-α)=1/8,则cosα+（根号3）sinα的值为____已知cosα-cosβ=1/2,sinα-sinβ=1/3,求cos(α+β)的值
为什么-[cos²(π/8)-sin²(π/8)]=-cos(π/4)
cos(π/32)*cos(π/16)*cos(π/8)=
计算sin²π/8-cos²π/8=
cos平方π/8-sin平方π/8,