已知(a-2)^2+√b+1/2大于等于0 求-2(3b^2-2a^2)+3(ab+2b^2-a^2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 21:02:45
![已知(a-2)^2+√b+1/2大于等于0 求-2(3b^2-2a^2)+3(ab+2b^2-a^2)](/uploads/image/z/982152-0-2.jpg?t=%E5%B7%B2%E7%9F%A5%28a-2%29%5E2%2B%E2%88%9Ab%2B1%2F2%E5%A4%A7%E4%BA%8E%E7%AD%89%E4%BA%8E0+%E6%B1%82-2%283b%5E2-2a%5E2%29%2B3%28ab%2B2b%5E2-a%5E2%29)
x){}K5u4㌴uJ67zd]}vIgt4t45@|&H*PE|ڿɎzyںϦ|9wދ-!J:^
e'$'?~[]$5eCskmD(h9LT*
f"`m|xt*ka$ف 3
已知(a-2)^2+√b+1/2大于等于0 求-2(3b^2-2a^2)+3(ab+2b^2-a^2)
已知(a-2)^2+√b+1/2大于等于0 求-2(3b^2-2a^2)+3(ab+2b^2-a^2)
已知(a-2)^2+√b+1/2大于等于0 求-2(3b^2-2a^2)+3(ab+2b^2-a^2)
根号下和完全平方非负
所以a-2=0
b+1/2=0
a=2,b=-1/2
代数式=-6b²+4a²+3ab+6b²-3a²
=a²+3ab
=4+3×2×(-1/2)
=4-3
=1