(2x-1)²-9x²=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 19:27:36
xk@Re7ߙE$iO",TDzP=c!ٴlTv#ă;mT`TA1wSo[= !C]WueY k6ųE^B;Q&i`MqtͱFإql8+Q :~nS' [.' d^b(X,,bf{~@(">d0+)S@$&H'
b&$`PJTاPދHI2jQOyL)UcS0j$M12u{ҥL1h״Д6jkW}rv~ﱫNp뵝`Pݎ.e}~^ZWs3 Ac#x؈c$O\41-l;- T
(2x-1)²-9x²=0
(2x-1)²-9x²=0
(2x-1)²-9x²=0
解方程(2x-1)²-9x²=0
(2x-1+3x)(2x-1-3x)=(5x-1)(-x-1)=0
故x₁=1/5;x₂=-1.
(2x-1)^2-9x^2=0
(2x-1+3x)(2x-1-3x)=0
(5x-1)(-x-1)=0
x1=1/5 x2=-1
4x-4x+1-9x=0
-5x-4x+1=0
5x+4x-1=0
(5x-1)(x+1)=0
x=1/5或者x=-1
(2x-1)2-9x2=0
4x2-4x+1-9x2=0
-5x2-4x+1=0
用求根公式可得x1=-1
x2=1/5
x=0.2或-1
x=1,-1,0.2,-0.2