lim(x→1)3x^2-3/3x^2-2x-1怎么解呢

lim x→∞(2x+1)/(3x-4) lim(x→0)2x^3-x+1 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim(x->无穷大){(2^x-3^x)/2}^(1/x) lim(x->0)((2-x)/(3-x))^1/x lim(x→1)(x^3-3x+2)/(x^3-x^2-x+1) lim(x→1)[(x^(3x-2)-x)sin2(x-1)]/(x-1)^3 lim((√1+x^2)+x)/((√x^3+x)-x)x→+无穷大 1.lim x->∞ （2x/x^2+1)*cosx 2..lim x->∞{ [(x^2-x)arctanx]/x^3-x-5}3..lim x->0 （e^x-e^-x-2x)/(x-sinx) 4..lim x->0 (sinx-x)/(x^3) 5..lim x->0 (x^2*tanx)/(x-tanx) 6..lim x->0 (1+3/x)^2x 7..lim x->0 (1+2x)^(3/sinx) 8.lim x->∞ (x/1+x)^(x-3) 9..li lim(x+1)^x+1(x+3)^x+3/x^2x+4 x趋于无穷 1.lim x→0 3x/(sinx-x)2.lim x→0 (1-cosmx)/x^23.lim x→0 sin4x/[(√x+2)-√2]4.lim h →0 [sin(x+h)-sin(x-h)]/h lim(x→∞)(4x^3+2x-1)/(2x^3-3x+1) lim(x→∞)(2x^3-x^2-3)/(x^3-x+1) lim x→1 (x^2-4x+3)/(x^4-4x^2+3) lim(x→∞)[（x^3+x^2+x^1+1)^(1/3) - x] 的极限. lim x→0 (x^2+2x-1)/(x^3-2x)的极限是多少 lim(x→∞)[(X^2+2x+5)/(3x^2-x+1) = lim(x→0)[(1+X)(1+2X)(1+3x)-1]/x