x+2y+4z=1 x^2+y^2+z^2 最小值 Y=sin a*(cos a)^2 最大值a>0 b>0 2c>a+b,求证:c-(c^2-ab)^(1/2)< a < c+(c^2-ab)^(1/2)三道不等式的题,
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![x+2y+4z=1 x^2+y^2+z^2 最小值 Y=sin a*(cos a)^2 最大值a>0 b>0 2c>a+b,求证:c-(c^2-ab)^(1/2)< a < c+(c^2-ab)^(1/2)三道不等式的题,](/uploads/image/z/9899391-39-1.jpg?t=x%2B2y%2B4z%3D1+x%5E2%2By%5E2%2Bz%5E2+%E6%9C%80%E5%B0%8F%E5%80%BC+Y%3Dsin+a%2A%EF%BC%88cos+a%29%5E2+%E6%9C%80%E5%A4%A7%E5%80%BCa%3E0+b%3E0+2c%3Ea%2Bb%2C%E6%B1%82%E8%AF%81%EF%BC%9Ac-%EF%BC%88c%5E2-ab%29%5E%281%2F2%29%3C+a+%3C+c%2B%EF%BC%88c%5E2-ab%29%5E%281%2F2%29%E4%B8%89%E9%81%93%E4%B8%8D%E7%AD%89%E5%BC%8F%E7%9A%84%E9%A2%98%2C)
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