作业帮求[4-2^(n+1)]/[2^n+2^(n+2)]的极限 就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?分子分母要同除以什么?求[4-2^(n+1)]/[2^n+2^(n+2)]的极限就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?分子分母要同除以什么?
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/21 04:51:27
![求[4-2^(n+1)]/[2^n+2^(n+2)]的极限 就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?分子分母要同除以什么?求[4-2^(n+1)]/[2^n+2^(n+2)]的极限就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?分子分母要同除以什么?](/uploads/image/z/9902853-45-3.jpg?t=%E6%B1%82%5B4-2%5E%28n%2B1%29%5D%2F%5B2%5En%2B2%5E%28n%2B2%29%5D%E7%9A%84%E6%9E%81%E9%99%90+%E5%B0%B1%E6%98%AFlim%5B4-2%5E%28n%2B1%29%5D%2F%5B2%5En%2B2%5E%28n%2B2%29%5D%3D%3F%E5%88%86%E5%AD%90%E5%88%86%E6%AF%8D%E8%A6%81%E5%90%8C%E9%99%A4%E4%BB%A5%E4%BB%80%E4%B9%88%3F%E6%B1%82%5B4-2%5E%28n%2B1%29%5D%2F%5B2%5En%2B2%5E%28n%2B2%29%5D%E7%9A%84%E6%9E%81%E9%99%90%E5%B0%B1%E6%98%AFlim%5B4-2%5E%28n%2B1%29%5D%2F%5B2%5En%2B2%5E%28n%2B2%29%5D%3D%3F%E5%88%86%E5%AD%90%E5%88%86%E6%AF%8D%E8%A6%81%E5%90%8C%E9%99%A4%E4%BB%A5%E4%BB%80%E4%B9%88%3F)
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求[4-2^(n+1)]/[2^n+2^(n+2)]的极限 就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?分子分母要同除以什么?求[4-2^(n+1)]/[2^n+2^(n+2)]的极限就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?分子分母要同除以什么?
求[4-2^(n+1)]/[2^n+2^(n+2)]的极限 就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?分子分母要同除以什么?
求[4-2^(n+1)]/[2^n+2^(n+2)]的极限
就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?
分子分母要同除以什么?
求[4-2^(n+1)]/[2^n+2^(n+2)]的极限 就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?分子分母要同除以什么?求[4-2^(n+1)]/[2^n+2^(n+2)]的极限就是lim[4-2^(n+1)]/[2^n+2^(n+2)]=?分子分母要同除以什么?
lim[4-2^(n+1)]/[2^n+2^(n+2)]=
同时除以2^(n+2)
原式=lim[4/2^(n+2) - 1/2]/[1/4+1]
=lim(0-1/2)/(5/4)
=-2/5