解分式方程4/(x²-1)+(x+2)/(1-x)=-1
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解分式方程4/(x²-1)+(x+2)/(1-x)=-1
解分式方程4/(x²-1)+(x+2)/(1-x)=-1
解分式方程4/(x²-1)+(x+2)/(1-x)=-1
我附图给你解答,
4/(x²-1)+(x+2)/(1-x)=-1
4/(x+1)(x-1)-(x+2)/(x-1)=-1
都乘以(x+1)(x-1)得:4-(x+2)(x+1)=-x²+1
4-x²-3x-2=-x²+1
解得:x=1/3
经检验是原方程的根
4/(x²-1)+(x+2)/(1-x)=-1
4/(x²-1)-(x+2)/(x-1)=-1 两边同时乘以x²-1得
4-(x+2)(x+1)=1-x²
4-x²-3x-2=1-x²
x²+3x-x²=4-2-1
3x=1
x=1/3