计算:[(3x+1)(9x^2-3x+1)+(3x-1)(9x^+3x+1)]÷[(4x+1)^-(4x-1)^2]
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 20:26:21
xOKAa;zo!Ow+ust:DP!jFإo"ַh;_NjX\a-Kz5_9E$JHZ^WCUu2_vGߥAPJ{;{lKөKi H|mx ]O68p3&06lA5Z%
A#ɈnK4%P K.,N-ƙҢL@FmW*r%L\UqD4 "TfGl&Ȋ.j]>aGqtGwd1 gOh~?Lۣh>xTx=SD8:
4>m--
计算:[(3x+1)(9x^2-3x+1)+(3x-1)(9x^+3x+1)]÷[(4x+1)^-(4x-1)^2]
计算:[(3x+1)(9x^2-3x+1)+(3x-1)(9x^+3x+1)]÷[(4x+1)^
-(4x-1)^2]
计算:[(3x+1)(9x^2-3x+1)+(3x-1)(9x^+3x+1)]÷[(4x+1)^-(4x-1)^2]
题目中两个位置少“次方”,如果是“^2”,结果如上图.
计算 2+x+3/x-1*x^2-2x+1/x^2+6x+9
计算(x+1)(x+2)(x+3)(x+4)
计算:(x+1)(x-2)(x-3)(x-6)
计算 x(x+3)-(x-1)(x-2)
如何计算 (x+1)(x+2)(x+3)(x+4)
计算(X-1)(X-2)(X-3)(X-4)
(x-1)(x-2)(x-3)(x-4)-24计算
计算:x/(x-1)-(x+3)/(x^-1)*(x^2+2x+1)/(x+3)
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
计算:1-2x+x^2/x-x^3*xy+x^2y/x-x^2
计算:1/(x+1) * [(x-3)/(x^2 + 6x + 9) + 2/(3+x)] - x/(x^2 - 9)
(x+1/x+3)²÷x²-1/x²-9·(x-2)(x+1)/x-3计算
计算:(1)/(x-3)÷(x+2)/(x^2-9)-(1)/(x^2+5x+6)
计算:(x+1)x=7 (x-1)(x+2)=30 (3-x)(3-x)+x=9
计算1/x-3 - 6/x*x-9 - x-1/6-2x
4x²-1/3x²-x·9x³-x/2x^4-x³计算 急
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
计算:x/(1-x)-1/(x-3)