log2(5-x)
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log2(5-x)
log2(5-x)
log2(5-x)
因为log2a单调递增,所以5-x<3x+1,所以x>1,又因为5-x和3x+1都要大于0,所以最后1<x<5
log2 5 x log2 5等于log2 25还是什么?
log2 (5-x)
log2 (5-x)
log2(5-x)
log2(5-x)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
解不等式:|log2(x-1)|+log2(5-x)
解2log2^(x-5)=log2^(x-1)+1
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
log2^(x^log2^x)=?
log2(x-2)=log4(5-x)
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
不等式log2为低(5-x)
log2(x^2-3)=5 计算
解不等式 log2(X平方+2X)>log2分之一(5-2X分之1)
求函数f(x)=2+log2^x+5/log2^x,(0
高一不等式,要过程(1) log2(x加5)>log2(3-x) (2) 2^x