(x-z-20)²+(3x-6y+3)²+|3y+2z-8|=0 求x z y
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/29 22:47:57
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(x-z-20)²+(3x-6y+3)²+|3y+2z-8|=0 求x z y
(x-z-20)²+(3x-6y+3)²+|3y+2z-8|=0 求x z y
(x-z-20)²+(3x-6y+3)²+|3y+2z-8|=0 求x z y
(x-z-20)²+(3x-6y+3)²+|3y+2z-8|=0
(x-z-20)²大于等于0
(3x-6y+3)²大于等于0
|3y+2z-8|大于等于0
所以他们都等于0
x-z-20=0
3x-6y+3=0
3y+2z-8=0
解出xyz
因为(x-z-20)²+(3x-6y+3)²+|3y+2z-8|=0
所以x-z-20=0,3x-6y+3=0,3y+2z-8=0
解方程组得x=93/7,y=50/7,z=-47/7
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