求过圆C1:x²+y²+4x+y+1=0与圆C2:x²+y²+2x+2y+1=0的交点,且面积最小的圆的方程.
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求过圆C1:x²+y²+4x+y+1=0与圆C2:x²+y²+2x+2y+1=0的交点,且面积最小的圆的方程.
求过圆C1:x²+y²+4x+y+1=0与圆C2:x²+y²+2x+2y+1=0的交点,且面积最小的圆的方程.
求过圆C1:x²+y²+4x+y+1=0与圆C2:x²+y²+2x+2y+1=0的交点,且面积最小的圆的方程.
方程1和2 ,用2减1得x,y的关系:2x=y.代入方程1中得5x^2+6x+1=0 得两点(-1,-2);(-0.2,-0.4).当这两点的连线段是这个圆的直径时这个圆的面积最小
联立求得点(1,1),(1/5,2/5)然后这两点作为直径做圆。