(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y
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(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y
(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y
(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y
4X
2x*2=1/2
4x=1
10xy=5y/2
由以上可求
3)(3x²y-xy²+2xy)÷二分之一xy 4) (x-3)×(x+3)-(x+10×(x+3)
(xy-x²)÷(x²-2xy+y²/xy)×(x-y/x²)
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
先化简,再求值:[-xy/(x-y)^2]^4*(x^2-xy/x)3*x^4/y^10÷(x/xy-y^2)^5先化简,再求值:[-(xy)/(x-y)^2]^4*(x^2-xy/x)3*x^4/y^10÷(x/xy-y^2)^5,其中x=-2,y=4.
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