已知x(x²+4)分之4 = x分之A + ( x²+4)分之Bx+C,则A,B,C各等于多少?已知x(x²+4)分之4=x分之A+x²+4分之Bx+C,则A,B,C各等于多少?
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![已知x(x²+4)分之4 = x分之A + ( x²+4)分之Bx+C,则A,B,C各等于多少?已知x(x²+4)分之4=x分之A+x²+4分之Bx+C,则A,B,C各等于多少?](/uploads/image/z/996484-4-4.jpg?t=%E5%B7%B2%E7%9F%A5x%28x%26%23178%3B%2B4%29%E5%88%86%E4%B9%8B4+%3D+x%E5%88%86%E4%B9%8BA+%2B+%28+x%26%23178%3B%2B4%EF%BC%89%E5%88%86%E4%B9%8BBx%2BC%2C%E5%88%99A%2CB%2CC%E5%90%84%E7%AD%89%E4%BA%8E%E5%A4%9A%E5%B0%91%3F%E5%B7%B2%E7%9F%A5x%28x%26%23178%3B%2B4%29%E5%88%86%E4%B9%8B4%3Dx%E5%88%86%E4%B9%8BA%2Bx%26%23178%3B%2B4%E5%88%86%E4%B9%8BBx%2BC%2C%E5%88%99A%2CB%2CC%E5%90%84%E7%AD%89%E4%BA%8E%E5%A4%9A%E5%B0%91%3F)
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已知x(x²+4)分之4 = x分之A + ( x²+4)分之Bx+C,则A,B,C各等于多少?已知x(x²+4)分之4=x分之A+x²+4分之Bx+C,则A,B,C各等于多少?
已知x(x²+4)分之4 = x分之A + ( x²+4)分之Bx+C,则A,B,C各等于多少?
已知x(x²+4)分之4=x分之A+x²+4分之Bx+C,则A,B,C各等于多少?
已知x(x²+4)分之4 = x分之A + ( x²+4)分之Bx+C,则A,B,C各等于多少?已知x(x²+4)分之4=x分之A+x²+4分之Bx+C,则A,B,C各等于多少?
两边同乘x(x²+4)得:
4=A(x²+4)+(Bx+C)x
4=(A+B)x²+Cx+4A
则:A+B=0,
C=0
4A=4
解得:A=1,B=-1,C=0