若4x²+y²-4x+10y+26=0,试求x,y的值
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若4x²+y²-4x+10y+26=0,试求x,y的值
若4x²+y²-4x+10y+26=0,试求x,y的值
若4x²+y²-4x+10y+26=0,试求x,y的值
即(4x²-4x+1)+(y²+10y+25)=0
(2x-1)²+(y+5)²=0
所以2x-1=0,y+5=0
x=1/2,y=-5
4x²+y²-4x+10y+26=0
4x²-4x+1+y²+10y+25=0
(2x-1)^2+(y+5)^2=0
(2x-1)^2=0,x=1\2
(y+5)^2=0 ,y=-5