x+y+z=-1 4x-2y+3z=5 y-z=8-2x
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x+y+z=-1 4x-2y+3z=5 y-z=8-2x
x+y+z=-1 4x-2y+3z=5 y-z=8-2x
x+y+z=-1 4x-2y+3z=5 y-z=8-2x
x+y+z=-1 ①
4x-2y+3z=5 ②
y-z=8-2x ③
由①×2+②得:
6x+5z=3 ④
由①-③得:
x+2z=-9+2x
即 x=9+2z ⑤
代入④得:
54+12z+5z=3
17z=51
z=3
代入⑤得:
x=9+2×3=15
把x=15,z=3代入①得:
15+y+3=-1
y=-19
所以方程组的解为x=15
y=-19
z=3
x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5
x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快
3x-y+2z=-1 4x+y+z=5 x-2y-z=-2
x+y+z=-1 4x-2y+3z=5 y-z=8-2x
x+y+z=1 4x+5y-z=6 x+2y-z=3
{x+y+z=1 {x+3y+7z=2 {x+5y+19z=4
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
三元一次方程 X-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 X=?Y=?Z=?
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
x+2y-z=-5 x+y+2z=-1 3x+4y-2z=-12x+2y-z=3 2x+y+3z=0 4x+z=-4
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
解三元一次方程组1、x+y-z=4 2x-y+z=5 x-3y+z=-2 2、y+2z=-2 3x+y-4z=1 2x-y+2z=8 3、x-2y+z=-1 x+y+z=2x+2y+3z=-1
{5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-1
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
x/2=y/3=z/5 x+3y-z/x-3y+z
x+y/2=z+x/3=y+z/4 x+y+z=27
x+2y=3x+2z=4y+z 求x:y:z