方程(1+√2)x²-(1-√2)x=0解是?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 22:27:55
![方程(1+√2)x²-(1-√2)x=0解是?](/uploads/image/z/999156-12-6.jpg?t=%E6%96%B9%E7%A8%8B%EF%BC%881%2B%E2%88%9A2%EF%BC%89x%26%23178%3B-%EF%BC%881-%E2%88%9A2%EF%BC%89x%3D0%E8%A7%A3%E6%98%AF%3F)
x){6mtj?e~Og.HL&fkbg3$铮IΆLPVWEM,TMi/Z+lujŁ !d [#0F 1U0X+,Q\\]$R4D =
方程(1+√2)x²-(1-√2)x=0解是?
方程(1+√2)x²-(1-√2)x=0解是?
方程(1+√2)x²-(1-√2)x=0解是?
(1+√2)x²-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
X=0或者x=(1-√2)/(1+√2)=(1-√2)(√2-1)/(1+√2)(√2-1)=2√2-3
(1+√2)x²-(1-√2)x=0
(1+√2)x²=(1-√2)x
x²=x
x=0 x=1