[x﹙x²y²-xy)-y(x²-x³y﹚]÷3x²y
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[x﹙x²y²-xy)-y(x²-x³y﹚]÷3x²y
[x﹙x²y²-xy)-y(x²-x³y﹚]÷3x²y
[x﹙x²y²-xy)-y(x²-x³y﹚]÷3x²y
=[(xy-1)-(1-xy)]/3
=2xy/3
话说这问题为啥会分类在极品飞车里……