(1/2006*1/2005*…1/2*1)^100*(2006*2005*…*2*1)^100=
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/09 02:33:22
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(1/2006*1/2005*…1/2*1)^100*(2006*2005*…*2*1)^100=
(1/2006*1/2005*…1/2*1)^100*(2006*2005*…*2*1)^100=
2006/1+2006/2+2006/3+…+2006/2004+2006/2005等于多少要算式,
因式分解:2 2007-2 2006-2 2005-……-1
(2006-1/2-1/3-……-1/2005)(1/2+1/3+……+1/2006)-(2006-1/2-1/3-……-1/2006)(1/2+1/3……+1/2005)=?
(2007-1)+(2006-2)+(2005-3)+……+(1005-1003)
1-2+3-4……+2005-2006
(-1)+(+2)+(-3)+(+4)+……+(-2005)+(+2006)+(-2007)+(+2008)
(+1)+(-2)+(+3)+(-4)+……+(+2005)+(-2006)+2007
计算:(1/2006-1)(1/2005-1)(1/2004)… (1/3-1)(1/2-1).
|1/2008-1/2007|+|1/2007-1/2006|+|1/2006-1/2005|+|1/2005-1/2004|+……+|1/3-1/2|+|1/2-1|
(1/2006-1)x(1/2005-1)x……(1/2-1)等于多少
2008×2007-2007×2006+2006×2005-2005×2004+…+2×1
1+2+3+…+2004+2005+2006= 1+3+5+…+2001+2003+2005+2007
|1/2008-1/2007|+|1/2007-1/2006|+|1/2006-1/2005|+|1/2005-1/2004|+…+|1/3-1/2|+|1/2-1|=
1+2-3-4+5…+2005+2006-2007-2008
(+1)+(-2)+(+3)+(-4)+…+(+2005)+(-2006)+2007怎么做?
1+2+3+4+···+2005+2006)/(1-1/1004)*(1-1/1005)……(1-1/2005)*(1-1/2006)=