证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+y)/2)
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三角不等式证明证明sin(x+y)+sin(y+z)+sin(z+x)>sinx+siny+sinz+sin(x+y+z)
证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+y)/2)
将sinx+siny+sinz-sin(x+y+z)化为积的形式
证明sin(x+y)sin(x-y)=sinx-siny
将sinx+siny+sinz-sin(x+y+z)化为积的形式
一道关于三角函数的不等式证明题已知0≤x<y<z≤π求证:(siny-sinx)/(y-x)>(sinz-siny)/(z-y)
证明不等式|siny-sinx|
m=(sinx)/sin(y-z),n=(siny)/sin(z-x),p=(sinz)/sin(x-y),求mn+np+pm.
已知x,y,z属于(0,派/2),sin^2x+sin^2y+sin^2z=1,求(sinx+siny+sinz)/(cosx+cosy+cosz)的最大值
证明sinx+cos(x+y)siny/cosx-sin(x+y)siny=tan(x+y)
1.已知8cos(2x+y)+5cosy=0,求tan(x+y)*tanx的值.2.已知关于x的方程x^2+px+q=0的两根是tanx,tany,求sin(x+y)/cos(x-y)的值.3.化简:sin(x-y)/(sinx*siny)+sin(y-z)/(siny*sinz)+sin(z-x)/(sinz*sinx).
证明 [sin(2x+y)/sinx]-2cos(x+y)=siny/sinx
证明cosx(cosx-cosy)+sinx(sinx-siny)=2sin(x-y)/2
证明sin(x+y)sin(x-y)=(sinx)^2-(siny)^2.
sinx+siny+sinz=0;cosx+cosy+cosz=0;求cos(x-y)
请问,如何证明sinx+siny=2*sin(x+y/2)*cos(x-y/2)
|sinx-siny|≤|x-y|如何证明
证明|x-y|≥|sinx-siny|