log2(x+1)+log2(x+8)=3的解集是?
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log2 (x+1)+log2 x=log6
log2(x+1)+log2(x+8)=3的解集是?
log2^(x^log2^x)=?
解方程:log2(x+4)+log2(x-1)=1+log2(x+8)
log2(x)=-1
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8)
f(x)=log2(x/8)*log2(2/x)
log4(log2^x)=log2(log4^x)求log2^x
log2(-x)=x+
解方程:log2(x)+log2(x-8)=7
解不等式log2(4x+8)>log2(2x+1)
解方程log2(2-x)=log2(x-1)+1
解2log2^(x-5)=log2^(x-1)+1
求解log2(3x)=log2(2x+1)
|[log2(x)]^2-3log2(x)+1|
log2(x+1)>log2(3-x)
log2(log5 x)=-1