x y x-1 2y-1若 9 + 4 =1,求 3 +2 的最大值.搞错了……若9^x+4^y=1,求3^(x-1)+2^(2y-1)的最大值.另外不是对数,是指数……
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(x+y)(x-y)+4(y-1)
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
4(x-y+1)+y(y-2x)4x^4-13x²+9
9y=3x-(x-1),4(x+y)-(2x+4)=8y
若x=-1/4,能否确定代数式(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)的值?
若x-y=1 化简(x+y)(x^2+y^2)(x^4+y^4)(x^8+y^8)(x^16+y^16)
若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是()
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
把4(x-y+1)+y(y-2x)因式分解
y(y+2)+4x(x-y-1)因式分解是多少
若x*x+y*y=x+y-1/2,求x,y的值如题
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
(x-y)/4+(x+y)/5=1/4 (x+y)/9-(x-y)/3=//2(x-y)/4+(x+y)/5=1/4(x+y)/9-(x-y)/3=//2
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
把(x+y),(x-y)个作为一个整体合并同类项1,7(x+y)-2(x+y)-4(x+y)+2(x+y)2,(x-y)²+2(x-y)-(x-y)-2(x-y)²
已知4x=9y求(1)x+y/y (2)y-x/2x有关比例的
解二元一次方程 {3(x+y)-4(x-y)=-9 x+y/2+x-y/6=1
因式分解 (1).(x+y)(x+y-6)+9 (2).x²-16y²-x-4y