-π/2>f(x)+g(x)f(x)-g(x)sin{g(x)}
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/05 12:37:21
x)=ߠodQ$@]83D$飫qpAv3lQVp)[_MqCH\؆Z}#-}P{:Ny}ӞiϗlmζsԔ-jNӝ/dWHǓN}qC=߽
i@*?tO[;Yb'{ Yϗox?Y{zl{:t*ntͅXp =c
-π/2>f(x)+g(x)f(x)-g(x)sin{g(x)}
max{f(x),g(x)}=1/2(f(x)+g(x)+|f(x)-g(x)|
f(x)=2x-1,g(x)=x^2,则f[g(x)]=?,g[f(x)]=?,f[f(x)]=?,g[g(x)]=?
设f(x)=x^2 ,g(x)=2^x 则f[g(x)]= g[f(x)]=f[g(x)]= g[f(x)]=
求f[g(x)]
f(x)=g(x-2) f(-x)=g多少?f(x)=g(x-2) f(-x)是等于g(-x+2)还是g(-x-2)?
| f(x) | / | g(x) | = | f(x)/g(x) | 吗?
(g(x)/f(x))'公式?
g(x)/f(x)求导
f(x)g(x)不定积分
设f(x)=x^2,g(x)=2^x 求f(g(x)) 和g(f(x))
f(x)=x^2,g(x)=2^x求f[g(x)]= g[f(x)]=
证明(f(x)*g(x))'=f'(x)*g(x)+g'(x)*f(x)
证明(f(x)*g(x))'=f(x)'*g(x)+g(x)'*f(x)
设f(x)=2^x,g(x)=4^x,g(g(x))>g(f(x))>f(g(x)),求X的取值范围
已知f(x)=3x+2,g(x)=x^2-1,求f(x+1),f[f(x0],f[g(x)],g[f(x)]
f[g(x)]=f(x)*g(x)?
设f(x)=x^2,g(x)-2^x,求g(f(x)