m^2-5m+5=1咋么算
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/21 17:05:31
x)ˍ3565|:Ύ$c//y:mOM35~kw<9Yt
,0+,\]M aik QdkcZ~qAb1 jN
m*m-5m-1=0则2m*m-5m+1/m*m
(m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)=
m-2m-3m+4m-5m-6m+7m.2004m=?
(m+3m+5m.+2013m)-(2m+4m+6m+.+2012m)=?
当m=1/2时,求15m²-9-{-4m²+[5m-8m²-(2m²-m)+9m²]-3m}
(m+3m+5m+7m+.+2009m)-(2m-4m-6m-.-2008m)=?
[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1,求m
当m= 时,2m(3m-5)+3m(1-2m)=14
化简3(m+1)^2-5(m-1)(m+1)+2m(m-1),其中m=3
化简求值m^2(m+4)+2m(m^2 -1)-3m^3,其中m=2/5
化简求值m^2(m+4)+2m(m^2 -1)-3m^3,其中m=2/5
已知m^2-5m+1=0,求m^3+1/m^3 和m-1/m的值
(2m^3+3m)-(m^3+5m-3m^3)-1,其中m=-1
化简|6-m|-|2m+1|+|m+5| (m
先化简再求值(3m²+5)(-3m²+5)-m²(7m+8)(7m+8)+(2m+1)(-2m-1),其中m=-1
(1m+3m+5m+...+2009m)-(2m+4m+6m+...=2008m)guo cheng (bu zhou)
式子m(m=1)(m+2)(m+3)(m+4)(m+5)(m+6)...(m+20)/20!可表示为组合问题解的详细点啊
计算(m+3m+5m……+2009m)—(2m+4m+6m+2008m)=