2lg2+lg2.lg2.2lg5+2lg5=?要写下了过程.
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2lg2(lg2+lg5)+2lg5得数
(lg2)^2+lg2*lg5+(lg5)^2=
lg2*lg50+lg5*lg20-2lg5*lg2
(lg5)平方+2*lg5*lg2+(lg2)平方
(lg2)^2+lg5*lg20
(lg2)^2+lg20*lg5
(lg5)^2+lg2*lg50
3+lg5+(lg2)^2
2lg5*lg2=
=(lg5)^2+lg2×lg5+lg2 =lg5×(lg5+lg2)+lg2麻烦问一下,这是咋做的
(lg5)^2+lg2*lg25+(lg2)^2
lg50+lg2*lg5+(lg2)^2=
lg^2 5+lg2*lg5+lg2=?
lg5*(1+lg2)+(lg2)^2=
lg5+2lg2+(lg2)=?
lg5+2lg2-lg2=什么
lg5-lg2分之一-lg25-2lg2
lg2(1+lg5)+(lg5)^2