3+lg5+(lg2)^2
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3+lg5+(lg2)^2
3+lg5+(lg2)^2
3+lg5+(lg2)^2
原式
=2lg5+(2/3)lg8+lg5*lg20+(lg2)^2
=2lg5+2lg2+lg5*(lg5+2lg2)+(lg2)^2
=2lg5+2lg2+(lg5)^2+2lg2lg5+(lg2)^2
=2lg10+(lg5+lg2)^2
=2+1
=3
3+lg5+(lg2)^2
求解3lg5+3lg2*lg5+3lg2^2~
2lg5+(lg2)^3*(2lg5+lg2)计算~
(lg²2-lg2*lg5+lg²)+3lg2*lg5
(lg2)^3+(lg5)^2=
求值:(lg2)^3+3(lg2)^2*lg5+3lg2*(lg5)^2+(lg5)^3
(lg2)^3+(lg5)^3+lg5*lg8=(lg2+lg5)[(lg2)^2-lg2*lg5+(lg5)^2]+lg5*lg2^3=1[(lg2)^2-lg2*lg5+(lg5)^2]+3lg5*lg2=(lg2)^2+(lg5)^2+2lg5*lg2=(lg2+lg5)^2=1网上看了看答案,可是第一步没有看懂.求得出第一步的过程,
lg2+lg5=?1-lg2=?1-lg5=?2lg5+2/3lg8+lg5*lg20+(lg2)2=?
lg2(lg5-lg2)-lg5(lg5+3lg2)等于
lg2(1+lg5)+(lg5)^2
计算:(lg5)^2 +lg2 *lg5
(lg5)^2+lg5.lg2=
(lg2)^3+(lg5)^3+3*lg2*lg5
2lg2(lg2+lg5)+2lg5得数
(lg2)^2+lg2*lg5+(lg5)^2=
(lg2)³+(lg5)³+3lg2×lg5
lg2*lg50+lg5*lg20-2lg5*lg2
(lg5)平方+2*lg5*lg2+(lg2)平方