已知cos (π/6 -α)=√3/3 ,求cos (5π/6 + α)-sin²(α -π/6)的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/30 19:41:48
x){}K47)ۨicγM`SPN83OMZF]Y-O$S8;`@tof@"]CmDPF.D.L#LzT=3@U@I(Quۓk]!\h6HhPP 1 <^
已知√3sinα+cosα=2/3,求cos(2α-π/3)
已知cos(π/6-α)=√3/3,求cos[(5π/6)+α]-sin^2(α-π/6)
已知cos(π/6+α)=√3/3,则cos(5π/6-α)的值为 ( )
已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为答案好像是(3-4√3)/10
已知tan²=3,求3cos²α-2sinα×cosα-4cos²α-6
已知cos(x-π/6)=-根号三分之三 则cos(x)+cos(x-π/3)的值是
已知sin(5π-α)=√2cos(3π/2+β),)√3cos(-α)=-√2cos(π+β),0
已知cosα=-八分之十七,α属于(π,二分之三派),求cos(α-六分之π)改为:已知cosα=8/17,α属于(π,3π/2),求cos(α- π/6)
已知cosα=√3/3,化简并求值:(1+(tan2α)^2)[cos(2α+π/3)+cos(2α-π/3)]
已知sin(3π-α)=√2cos﹙3∏/2+β﹚.√3cos(-α)=-√2cos(π+β),且0
已知cos(π/3-α)=根号3/3,求cos(2π/3+α)+cos2(7π/6+α)
已知√3sinα+cosα=2/3,则cos(2α+π/3)等于
【高一数学】已知函数fx=2cos^2x+cos(2x+π/3)已知函数fx=2cos²x+cos(2x+π/3)(1)f(α)=√3/3+1,0
已知cos(π/6-α)+sinα=(4倍根号3)/5,则cos(α-π/3)=
已知cos(π/6-α)=根号3/3,求cos(5π/6+α)的值
已知cos(π/6-α)=根号3/3,求cos(5π/6+α)的值
已知tan=2,求cos^4(π/3+α)-cos^4(α-π/6)的值
已知cosα=1/3,α属于(π,2π),则cosπ/2等于