已知sin(5π-α)=√2cos(3π/2+β),)√3cos(-α)=-√2cos(π+β),0

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 05:38:01
已知sin(5π-α)=√2cos(3π/2+β),)√3cos(-α)=-√2cos(π+β),0
x){}K34L7ۨicQr~}#s4u4B !.LMR>U/&

已知sin(5π-α)=√2cos(3π/2+β),)√3cos(-α)=-√2cos(π+β),0
已知sin(5π-α)=√2cos(3π/2+β),)√3cos(-α)=-√2cos(π+β),0

已知sin(5π-α)=√2cos(3π/2+β),)√3cos(-α)=-√2cos(π+β),0
sin(5∏-a)=√2cos(3∏/2+b)
√3cos(-a)=-√2cos(∏+b),即
sina=√2sinb
√3cosa=√2cosb,即
sina^2+3cosa^2=2
cosa^2=1/2
cosa=√2/或cosa=-√2/2
a=Л/4或a=3Л/4
所以a=Л/4、b=Л/6或a=3Л/4,b=5Л/6

已知sin(3π+α)=2cos(α-4π)求cos(π/2 -α)+5sin(π/2 +α)/2cos(π+α)-sin(-α) 【三角函数】已知sin(α-π)=2cos(2π-α),求[sin(π-α)+5cos(2π-α)]/[3cos(π-α)-sin(-α)] 已知√3sinα+cosα=2/3,求cos(2α-π/3) 已知sin(3π-α)=-2sin(π/2+α)则sinαcosα 已知cos(π/6-α)=√3/3,求cos[(5π/6)+α]-sin^2(α-π/6) 已知sinα-cosα=-√5/5 π 已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x 1.已知cosα=12/13,α∈(3π/2,2π),求cos(α+π/4).2.cos(α+β)=1/3,则(sinα-sinβ)^2+(cosα+cosβ)^2=?3.已知sinα=(√5)/5,sinβ=(√10)/10,α、β都是锐角,求cos(α+β)及α+β的值.4.已知锐角α、β满足sinα=(√5)/5,cosβ(√10)/1 求值:已知sinθ+cosθ=1/5,已知θ∈(0,π).求(1)sinθ*cosθ(2)sinθ-cosθ(3)tanθ 已知cosα-sinα=3√ 2/5,且π 1.sin的三次方(-α)cos(2π+α)tan(-α-π)2.cos(180°+α)sin(α+360°)/sin(-α-180°)cos(-180°-α)3.sin(2π-α)cos(π+α)cos(π/2+α)sin(9π/2+α)/cos(π-α)sin(3π-α)sin(-π-α)4.已知sinα=-3/5,求cosα,tanα的值5.已知tanα=-根号下3,求 已知sin(5π-α)=√2cos(3π/2+β),)√3cos(-α)=-√2cos(π+β),0 已知sin(7π-α)-3cos(3π/2+α)=2,则(sin(π-α)+cos(π+α))/(sinα+cos(-α))的值是 已知sin(7π-α)-3cos(π-α)=2,则(sin(π-α)+cos(π+α))/(sinα+cos(-α))的值是 已知sin(7π-α)-3cos(π-α)=2,则(sin(π-α)+cos(π+α))/(sinα+cos(-α))的值是 已知α∈(π,2π) sinα+cosα=1/5 求sinα*cosα sinα-cosα 已知tan(3π+α)=2,求:1、(sinα+cosα)²;2、sinα-cosα/2sinα+cosα 已知tan(π-α)=2,求sin²α-2sinαcosα-cos²α/4cos²α-3sin²α+1