证明:x4+y4+z4-2x2y2-2x2z2-2y2z2能被x+y+z整除八年级寒假作业题目
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证明;x4+y4+z4-2x2y2-2x2y2-2y2z2能被(x+y+z)整除
因式分解:x4+y4+z4-2x2y2-2y2z2+2z2x2
证明:x4+y4+z4-2x2y2-2x2z2-2y2z2能被x+y+z整除八年级寒假作业题目
因式分解x4+y4+z4-2x2y2-2x2z2-2y2z2x,y,后的2为平方.
因式分解:x4+y4+z4-2x2y2-2y2z2-2z2x2 最好能有详细过程,谢谢
4x4+5x2y2+7xy3+2y4怎么因式分解?
已知x+y+z=0,求x4+y4+z4-2x2y-2y2z2-2z2x2的值有指数
x+y+z=1,x2+y2+z2=2,x3+y3+z3=3,x4+y4+z4=?
因式分解 x5n+xn+1 2a2-a2b+(b-2)(ab-a)2 x5+x4+x3+x2+x+1 x4+y4-2x2y2-2x2-2y2+1
已知x+y+z=1 x2+y2+z2=2 x3+y3+z3=3 求x4+y4+z4=?
已知:x-y+1=0,xy-2x-2y-7=0,求x2+y2以及4x2y2-x4-y4.
已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2=
x4-7x2y2+9y4因式分解
因式分解x4-7x2y2+81y4
x4-2x4y4+y4因式分解
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以(x2+y2/xy)2乘1/x+y的值
(1)-2ab2+4a2b-10b (2)x2y2+y4+x4 (3)25a4-10a2+1 (4)x2-x-6 (5) xy-xz+y-z (6)16-(x+y)2
因式分解:x4次方-2x²y²+y4次方