y = -x^2 + x + 2 \1 \1 \1 \1 \1 \1 \1 \1 \1 \1 \1 \1 \1 \1 \1 \1 \1 y = x^2 - x - 2 y= 3x +3 三个方程所围成的面积如y = -x^2 + x + 2 ,y = x^2 - x - 2,y= 3x +3,三个方程所围成的面积如何求解.
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