已知根号(2x-y-4)+根号(x-2y-5)=0,求根号(y^2+5x)的值
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已知x=2y,化简根号y/(根号x-根号y)-根号y/(根号x+根号y)
已知x=2y,化简根号y/(根号x-根号y)-根号y/(根号x+根号y)
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