f(x)=(log2^x)^2-log2^x+2怎么解

f(x)=log2(x/8)*log2(2/x) log2^(x^log2^x)=? log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 已知函数f(x)=log2(2-x)+log2(2+x)求f(x)的定义域 已知函数f(x)=log2^ ( x/4 ) ×log2^ (2x) (1)解不等式f(x)>0;(2)当x∈【1,4】时,求f(x)的值域f（x）=log2（2x）×log2（x／4）＝[（log2 2）+(log2 x)] ×[(log2 x) -(log2 4)]=[1+(log2 x)] ×[(log2 x) -2]=(log2 x)² - (log2 x) -2 f(x)=log2^x,那么log2^x=2x么 f(x)=(log2 X/4)*(log2 X/2),x∈[1/2,4]的值域 F(X)=|X|+|X-2| 求F(log2 3) log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8) 设f(log2 X)=2^x,则f(2log2 3）= f(x)=(log2^x)^2-log2^x+2怎么解 设函数f(x)=log2(4x)*log2(2x) 1/4 求函数f(x)=(log2 4x)(log2 2x)在1/4 求函数f(x)=(log2^x/4)log2^x/2)的最小值 求函数f(x)=2+log2^x+5/log2^x,(0 设函数f(x)=log2(4x)*log2(2x) 1/4