数列{an}前n项和为Sn,a1=1,a(n+1)=2Sn (n属于N+)《1》\x05求数列{an}的通项an《2》\x05求数列{n*an}的前n项Tn在等比数列{an}中,Sn=48,S2n=60,S3n=?在等比数列{an}中,a1=2,前n项和为Sn,若数列{(an)+1}也是等比数列
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/17 13:10:29
xUKoF+
$wjw)N.zoit¬/jTEڍj(Zl $$:KJT^pc;ofggfgVofM!׳<|}}'5%,liSZNg[!E^|6s18!B_H׀Vdv ?ޞHG)y&QM&oBby1 >ʿ=XjkK]"zl_R.vC~<:;8O
mء%dY@~:ٳgNE|>pq.B"VIrcLz[KQy}SRsXW'D
p:_`ʏ!B Rs\r2-=䇏S<>ɏ
P?A2Pw Ӛ5bchz8uy[I:3R8>Gi赢*Bs|*9+ٝy
A[1Rd!Ι{] fTh$<0q-iCmV\=P7wQ~ͦnկ1w1Tv}fHE/ҵ&$@QsJ{-x`-+]K̮zh@cܛ%wu!x
j.VGb<"3!8#(2*|\y{uڼp!I %0<Y0<Ng0nQ%1"~=~Wdu&EF580o&