Y=(x^2-2x-3)/(x^2+3x+2)的水平和垂直渐近线怎么求?
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3^x+2x=y,x
[2/3x-2/x+y(x+y/3x-x-y)]/x-y/x
化简:{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x
计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x
化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x
x(x-y)2-(y-x)3
函数,y=3x/(x^2+x+1) ,x
函数y=3x/(x^2+x+1) (x
化简 3x(x^2-x-1)-(x+1)(3x^-x) X^3(x-y)+x(y-x)
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
(x+y)(x-y)+(x-y)平方-(x-y)(3x-y) 其中x=-2 y=3分之一
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
(x+y)(2x-3y)=?
(x^3-2x^2+xy^2)/(x-y)+(x+y)(y-x)=?
若2x=3y,则(x*x+y*y)/x*x=?
因式分解3x^2(x-y)+6x(y-x)
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
y=(2x*x-2x+3)/(x*x-x+1),求值域?