求方程y'+siny+x*cosy+x=0的同届
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求方程y'+siny+x*cosy+x=0的同届
求微分方程y'=(x+1-siny)/cosy的通解
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求由方程x-y+1/2siny=0所确认的隐函数的二阶导数y'=2/(2-cosy)到了二阶求导就不明白了(y')'=(2/(2-cosy))' 然后我算出了y''=(2-cosy-2siny)/(2-cosy)^2 我高数方面很差,求详解下.
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sinx+siny=√2/2 cosx+cosy=√6/2 求sin(x+y)求解答