x+z-3=0 2x-y+2z=2 x-y-z=-3
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证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
2x+z=10 x+y-z=4 3x-y-z=0
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x+2y=3x+2z=4y+z 求x:y:z
x/2=y/3=z/5 x+3y-z/x-3y+z
x+y/2=z+x/3=y+z/4 x+y+z=27
若x+y+z=3y=2z,则x/x+y+z=?
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之(x-z)(y-z)=?第三部分那个是 (y+z-2x)(x-2y+z)分之(x-z)(y-z)
X=3z X+y+z=12 X+2y-2z=10
x>=y>=z>0,求证:x^2*y/z+y^2*z/x+z^2*x/y>=x^2+y^2+z^2