y=1/2x^2-6x+21 =1/2(x^2-12x+36)+3 .为什么有个36?

{6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1 2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 解方程组6(x-y)-7(x+y)=21 2(x-y)-5(x+y)=-1 6（x-y)-7(xy)=21,2(x-y)-5(x+y)=-1 已知：2x+y=6,x-3y=1 求7y(x-3y)(x-3y)-2(3y-x)(3y-x) 1.(x-2y)(x+2y)-(x平方+y)(x平方-y) 2.(2x-y)(y+2x)-(2y+x)(2y-x)3.已知：x+y=6,x平方-y平方=48,求x,y的值4.x平方-2x分之x+2 -- x平方-4x+4分之x-1 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值 求值域 1,y=(x+2)/(x*x+3x+6) 2,y=3x/(x*x+4) 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 (x-2y)(x+y)-2x(-2x-3y)+6x(-x-y),其中x=-1,y=2 (x-2y)(x+y)-2x(-2x-3y)+6x(-x-y),其中x=-1,y=2要讲解和答题 （x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3. 2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2 解二元一次方程组：3(x+y)-4(x-y)=4,x+y/2+x-y/6+1x+y/2+x-y/6+1=1 x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 x+2y=2x+y+1=7x-y 求：2x-y?