x、y∈R,A={(x,y)|x2+y2=1},B={(x,y)| =1,a>0,b>0},当A∩B只有一个元素时,a,b的关系式是_________B的是x/a-y/b=1
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/20 09:43:37
xŐN@_c,p6>!zi$-Ap(p@1EP;-|
㟫ew̷cMXrBQ䪻ruJ
Z*k ff73ϧ
[_.x{"l<"xt aR
cɄ4sJr~2 7_/?H6jUE@Ҡ-FMA:R8S1W%NK#&K3rRRRC#*͠q
'geY-W_LTGk*Ix;6Ŷ$}rd[MivK^y5Zjׁ'(L
1.已知集合a=(x,y)/x,y∈R 且x2+y2=1 已知集合a=(x,y)/x,y∈R,且x1.已知集合a=(x,y)/x,y∈R 且x2+y2=1已知集合a=(x,y)/x,y∈R,且x2+y2=1 B=(x,y)/x,y∈R,且y=x则A∩B的元素个数为
已知x,y∈R,求证x2-xy+y2>=x+y-1
已知x,y∈R,且x2+y2
已知集合a=(x,y)/x,y∈R 且x2+y2=1已知集合a=(x,y)/x,y∈R,且x2+y2=1 B=(x,y)/x,y∈R,且y=x则A∩B的元素个数为抱歉没有悬赏了~
设x,y,z∈R+,求证 2z2-x2-y2/(x+y)+2x2-y2-z2/(y+z)≥x2+z2-2y2/(x+z)
设x,y,z∈R+,求证 2z2-x2-y2/(x+y)+2x2-y2-z2/(y+z)≥x2+z2-2y2/(x+z)
x2+xy+y2=1,且x,y∈R,则x2+y2的取值范围
求最值 若x,y∈R,且3x2+2y2=6,求x2+y2最大值和最小值.
x2+x+y2/x+y
设集合M={(x,y)|x2+y2=1,x∈R,y∈R},N={(x,y)|x2-y=0,x∈R,y∈R},则集合M∩N是多少
设集合M={(x,y)/x2+y2=1,x∈R,y∈R},N={(x,y)/x2-y=0,x∈R,Y∈R},则集合M和N的元素交集个数为?
若x,y∈R+且x2+y2/2=1则x√(1+y2)的最大值x2与y2表示平方
已知x.y∈R,求证x2+y2+1≥x+y+xy
已知x,y∈R,求证(x2+y2)2≥xy(x+y)2
已知X,Y,Z∈R,且X+Y+Z=1,求证X2+Y2+Z2≥1/3
x2+xy+y2=1,且x,y∈R,则x+y的取值范围
集合M={(x,y)|x2+y2=1},N=|(x,y)|x/a+y/b=1,a∈R,b∈R},若M交N不=空集,则a,b满足 A.a=
x2+y2 xy+x+y-1x y属于R 比较大小 x2+y2 xy+x+y-1