sin(2a)/(1+sina+cosa)=sina+cosa+1 怎么证明写错了 右边应该是减一!
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/07 03:17:13
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sina=2cosa,求(1)3sina+2cosa(2)sin²a+sina×cosa+3
证明sin^2a+sin^2β+1>sina*cosa+sina+sinβ
sina+cosa/sina-cosa=2 求sin^2a-2sinacosa+1
已知(sina+cosa)/(sina-cosa)=2,则:(3sina+cosa)/(2sina+3cosa)=?sin^2a-2sinacosa+1=?
已知sina+cosa/sina-cosa=2,计算下列各式的值(1)3sina+cosa/2sina+3cosa(2)sin^a-2sinacosa+1.
已知sin a+cos a=1/2 sina*cosa=?cos a/sina+sina/cosa=?
已知(sina+cosa)/(sina-cosa)=3 则2sin'a+(sina-cosa)'=?
已知tan(π-a)=2,求值:(1)2sin+2cosa/7sina+cosa(2)sina*cosa(3)4cosa^2+3sina^2
化简(1+sina+cosa)[sin(a/2)-cos(a/2)]/根号(2+2cosa) (0°
化简(1-sina-cosa)(1-sina+cosa)/sin²a-sina
(1-tana)/(1+tana)=2求(1)sina+cosa/(sina+2cosa) (2)sina-cosa(3)sin^2a-3cos^2a+1
sin(a+kπ)=2cos[a+(k+1)π].求5cosa+3sina/4sina-2cosa
sin(a+kπ)=2cos[a+(k+1)π].求5cosa+3sina/4sina-2cosa
sinA+sin(150-A)怎么转化到{(根号3 +2)/2}sinA+1/2cosA
已知tana/tana-1=-1,求下列各式的值(1)sina-3cosa/sina+cosa(2)sin^2a+sina*cosa+2
已知tana/(tana-1)=-1,求下列各式的值(1)sina-3cosa/sina+cosa(2)sin^2a+sina*cosa+2
1:已知sina+cosa=根2求sina cosa sin(4方)a+cos(4方)的值2:已知:sina+cosa=1/5(0
(2sin^2a+sin2a)/(1+tana) 整理 =[2sina(sina+cosa)]/[(sina+cosa)/cosa] =sin2a 这个过程怎么整理的看不懂,