高二数列有道解题看不懂已知数列a1=1,an=a(n-1)/3a(n-1)+1(n>=2)设bn=ana(n+1),求数列{an}的通项公式求数列{bn}的前n项和snAn=[A(n-1)]/[3A(n-1)+1]==> 1/An =3 +1/A(n-1)==> {1/an}为等差数列,首项 =1/A1 =1,公差 =31/An =1/A
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/09 22:49:03
xRJ@,['5Nt _pY\$0,BE[*Z
>ZuX#Ĭ̤Sq#3dvIna3ڿgq5Y}HFlEkˬ%^pְu}|(gaY*{t1n$fzb>|f\a