sin[α-(π/3)]+cos[α+(13π/6)]化简还有sin[α-(5π/4)]+cos[α+(π/2)]
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 13:28:26
xTJ@~wY7i6/rb_ BQ= }bb=u
-xq/77fvZݝ7${
-b{P0ہ@u8}9K.sjR⾻gUS#f%Ir"q@b@"R /ғDA $Ziw
CrqޔM,(KQB勺Ԭ0igDZNne{l/-ēgy3d+-R"Wg=I@L,p|0I<@r+OW(↗iy)")n95(
7x!>t$^^[ñ⣑6|o%3Z^Xz鉼0wGv>vCһMoGZ^3
3sinα=2cosα,则 cosα-sinα/cosα+sinα/ cos3sinα=2cosα,则cosα-sinα/cosα+sinα/cosα+sinα/cosα-sinα
利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ
化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α)
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α)
求值【sin(2π-α)sin(π+α)cos(-π-α)】/【sin(3π-α)-cos(π-α)】
已知sin(3π-α)=-2sin(π/2+α)则sinαcosα
设角a=-35π/6,则2sin(π+α)cos(π-α)-cos(π+α)/ 1+sin^2α+sin(π-α)-cos^2(π+α)sina=sin(-35π/6)=sin(-6π+π/6)=1/2 cosα=根号3/22sin(π+α)cos(π-α)-cos(π+α)/ [1+sin^2α+sin(π-α)-cos^2(π+α)]=2(-sinα)(-cosα)+cosα/[1+sin²
已知0<α<π/2,且3sinα=4cosα求(sin^2α+2sinαcosα)/(3cos^2α-1)求cos^2α+sinαcosα
已知6sin²α+sinαcosα-2cos²α=0,α∈(π/2,π),求值1).(sinα-3cosα)/(sinα-cosα);2).sinαcosα-sin²α;3).sin²α-3cosαsinα-2
已知sinα+cosα=4/5且3π/22,若sinα+sinβ+sinγ=0,cosα+cosβ+cosγ=0,则cos(α-β)的值
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π)
已知sin(3π+α)=2cos(α-4π)求cos(π/2 -α)+5sin(π/2 +α)/2cos(π+α)-sin(-α)
【三角函数】已知sin(α-π)=2cos(2π-α),求[sin(π-α)+5cos(2π-α)]/[3cos(π-α)-sin(-α)]
已知sin(7π-α)-3cos(3π/2+α)=2,则(sin(π-α)+cos(π+α))/(sinα+cos(-α))的值是
已知sin(7π-α)-3cos(π-α)=2,则(sin(π-α)+cos(π+α))/(sinα+cos(-α))的值是
已知sin(7π-α)-3cos(π-α)=2,则(sin(π-α)+cos(π+α))/(sinα+cos(-α))的值是
sinα=-2cosα,求sin^2α-3sinαcosα+1