2000(22-x)=2×1200x这道题的解题思路?拜托求解呀.一道列题:2000(22-x)=2×1200x他直接就变成2(22-x)=6x是怎么解的呀?两边同时除以400?(22-x)也应该除以400噻?请详答一下.谢谢!谢谢!
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若1+x+x*x+x*x*x=0,求x+x*x+x*x*x+.+x(2000次幂)
请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360
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35道.符号^代表平方.读起来就是(X的平方).1,x^-x-202,x^-9x+203,x^-9x-204,x^+9x+205,x^-18x+326,x^+14x-317,x^+18x+328,x^+14x-329,x^+19x+4810,x^+47x-4811,x^+13x-4812,x^+2x-4813,x^+26x+4814,x^-22x-4815,x^+17x+7216,x^+21x-10017,x^-x-7218,x
一元二次方程解答!x(5x+4)=5x+44x^2-45=31x-3x^2+22x-24=0(x+8)(x+1)= -12(3x+2)(x+3)=x+14
2x+(22-x)=40
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x+2x+(x+10)=90,x=?
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函数f(x)=x²-2x(x
X+X+2+X+4-(X+4)=26
(16x^4+4x^2+x)/x=?
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x/x^2+x+1=-1/22x^2/(x^2-x+1)+x-1/x^3-1
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