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来源:学生作业帮助网 编辑:作业帮 时间:2024/09/09 08:11:27
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解方程:X2--1/8(X2+2X)+X2+2X/3(X2--1)=11
2^5+5x2^4+10x2^3+10x2^2+5x2+1
已知x2-4x+1=0,求x2/(x2)2-3x2+1
y=3x/1+x2的值域1-X2/1+X2→2-(X2+1)/1+X2→-1 + 2/(1+X2)这一步怎么得到的,
计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2
若 x2-3x+1=0,求(2x2×x3-5x2×x2+2 x3-8x2 )÷(x2+1 )的值
(x2-3x)2-x(x2-3x)-2x2
4x2-3y2+2xy-4x2+5x2
(1/2)^3x2^3与(1/2x2)^3
2x2+1+2+3+2x2=
证明:x2+3/根号x2+1≥2根号2
(x2+1/x2-2)3展开式常数项是?
(x2-y2)-4(2x2-3y)
化简1/x2-3x+2 +1/x2-x +1/x2+x +1/x2+3x+2
求和Sn=1x2+3x2^2+5x2^3+…+(2n-1)x2^n
用杨辉三角规律计算下题 2^5-5x2^4+10x2^3-10x2^2+5x2-1
x2-3x+1=0,求x2+1/x2-2的值x2表示x的平方
Sn=1x2+3x2^2+5x2^3+...+(2n-1)2^n