如图,在矩形ABCD中,AC是对角线.点P为矩形外一点且满足AP=PC,AP⊥PC.PC交AD于点N,连接DP,过点P作PM⊥PD交D于点M(1)若AB=√5,AB=1/3BC,求矩形ABCD的面积(2)若CD=PM,求证:AC=AP+PN
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/10 07:54:05
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