化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)
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化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)
化简:(sin²αtanα+cos²α/tanα+2sinαcosα)sinαcosα
若a属于(0,π/2)试比较tanα、tan(tanα)、tan(sinα)
已知tanα=2,sinα
(cot^2)α((tan^2) α-(sin^2) α) 化简
化简(sin2α+2sin^2α)/(1-tanα)
化简cos^2(-α)-[tan(360°+α)/sin(-α)]
化简cos2(-α)-tan(2π+α)/sin(-α)
化简(sinα)^2tanα+cosα+(cosα)^2*1/tanα+2sinαcosα
化简:(cosα/2-sinα/2)(cosα/2+sinα/2)(1+tanαtanα/2)
化简sin^2α*tanα+cos^2α*1/tanα+2sinα*cosα
化简:sin^2α*tanα+(cos^2α)/(tanα)+2sinαcosα 只要结果
化简cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α)
cos(π-α)tan(2π-α)tan(π-α)/sin(π+α) 化简
化简sin(2π-α)tan(α+π)tan(-α-π)/
求证tan^2α-sin^2α=tan^2α*sin^2α
数学证明sin^2 αtan^2 α=tan^2 α-sin^2 α
求证:tan^2α-sin^α=tan^2乘sin^2α