log2 (1/49))×log3 (1/16)×log7 (1/27)
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log2 (1/49))×log3 (1/16)×log7 (1/27)
计算(log3 2)(log2 6-1)
log2 1-lg3×log3 2-lg5
log2 1-lg3×log3 2-lg5
为什么log3(2)=1/log2(3).
log2 24-1/log3 2=
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
1/log5^7+1/log3^7+1/log2^7 ,求值
log5[log3(log2^x)]=1,x=
计算:9^[log3(2)]-2[1+0.5log2(5)]
必修1数学:若log2[log3(log4X)]=0
已知log2(log3 x)=1,求x
已知log2(log3 x)=1,求x
已知log3 m=-1/log2 3,则m=
已知log3^(a+1)=2 ,则log2^a=?
已知log3 m=-1/log2 3,则m=
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
化简:log2 2+log5 1-3^(2log9 5)+(3log3 5)^2+3^log3 2