x/(3^3+4^3)+y/(3^3+6^3)=1 x/(5^3+4^3)+y/(5^3+6^3)=1 求证x+y=432 不得用三角函数!
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(y-x)+x(x-y)^3-(y-x)^4 因式分解
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
(3x-4y)(5x-4y)-(7x-8y)(6y-5x)
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
81/8*(-x-y)^6*(x-y)^3*4/9(x+y)^4*(y-x)^2
4x-3y/x-2y÷6y-8x/y-2x
(x+y)^6/(x+y)^4-(x-y)^5/(x-y)^3 化简 ..
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
(y-x)^4(x-y)^3+2(x-y)^6(y-x)
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3x+4y/x-y +3y/y-x -4x/x-y
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(3x-y)(3y+x)-(x-y)(x+y)
3x(x-y)³-6y(y-x)²