4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
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4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
第二个方程是不是写错了
2/(x+y)+3/(x-y)=6是这样吗
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
2(x+y)-3(x-y)=3 ,4(x+y)+3(x-y)=15
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
2元一次方程组 2/x+y+3/x-y=6 4(x+y)-3(x-y)=-20
解方程组;x+y/2=x-y/3=6 4(x+y)-3(x-y)=-20
已知2y-x=-3,求[4y(2x-y)-2x(2x-y)]/(2x-y
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y