1-sin^6a-cos^6a分之1-sin^4a-cos^4a 化简
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1-sin^6a-cos^6a分之1-sin^4a-cos^4a 化简
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
cos(6分之π-a)=2分之1,求sin(a+3分之牌)
化简1-sin^4a-cos^4a/1-sin^6a-cos^6a
(1-sin^6a-cos^6a)/(1-sin^4a-cos^4a)=?
(1-sin^4a-cos^4a)/(1-sin^6a-cos^6a)
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
化简:(sin^6a+cos^6a-1) / (sin^4ª+cos^4a-1)
若sin(6分之派-a)=3分之1,则cos(3分之2派-a)=
Sina+sin^2a=1,cos^2a+cos^s4a+cos^6a
当sinˆa+sin^2a=1求cos^+cos^6的值
=1-(sin^6a+cos^6a) ------(1)=1-(sin^a+cos^a)(sin^4 a-sin^acos6a+cos^4 a) --------(2)由(1)怎么能到(2)呢=1-(sin^6a+cos^6a)=1-(sin^2a+cos^2a)(sin^4 a-sin^2acos^2a+cos^4a)
化简1-cos^4a-sin^4a/1-cos^6-sin^6acos^6应为cos^6a
cosα+cos^2α=1求sin^2a+sin^6a+sin^8a=?
(1-sin(a)^6-cos(a)^6)/(1-sin(a)^4-cos(a)^4) (1-sin(a)^6-cos(a)^6)/(1-sin(a)^4-cos(a)^4)
(1-sin^6 a-cos^6 a)/(1-sin^4 a-cos^4 a)的化简结果
化简[1-cos^4(A)-sin^4(A)]/[1-cos^6(A)-sin^6(A)] 等于多少?