若y=√x-5+√5-x+2,求3x+5y的平方根
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/19 20:43:40
x){ѽQǬ
]Sm e[mlcqiY-Own~6m;mIP_`gC@U:<7Y@)X
U|DYgÓKu*lܮ. O[BV!+jkQ
Ɏ]6$Am<؊zG[]j vR90ˁB@`5AijFXmngk 6HCX`'S" J
若x>0,y>0,且√x(√x+√y)=3√y(√x+5√y),求2x+2√x*√y+3y/x-√x*√y+y
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
若x>o,y>o,且根号x(根号x+根号y)=3根号y(根号x+5根号y)求x+根号xy分之2x-根号xy-5y式子是√x(√x+√y)=3√y(√x+5√y),求x+√xy分之2x-√xy-5y
y=x^5+√x+1/x^3 ,求导数结果是y’=2x-5/2x^-7/2-3x^-4,对y求导数
已知:3x-5y=0,求x/y,x-y/y,x-y/x
已知4x²+y²-4x-6y+10=0求(2/3x(√9x)+(y²√x/y³)×(x²√1/x×5x√y/x)的值
已知4x²+y²-4x-6y+10=0求(2/3x(√9x)+(y²√x/y³)-(x²√1/x-5x√y/x)的值
已知4x²+y²-4x-6y+10=0,求[(2/3)x√(9x)+y²√(x/y³)-(x²√(1/x)-5x√(y/x)的值
用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+.
√x(√x+2√y)=√y(6√x+5√y,求x-3√xy+2y/x+√xy-6y
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
已知:x*x+√3y=√5,y*y+√3x=√5,且x≠y,求 y/x+x/y
若实数X,Y满足x²+y²-4x-2y+5=0求√x+y/√8y-2x
若(3x-y+5)²+√2x-y+3=0,求x-y的值
若x-y/x+y=5,求x-y/2x+2y+5x+5y/3x-3y的值
若x+y分之x-y=3,求式子x+y分之5(x-y)—2(x-y)分之x+y的值
若x-y分之x+y=3,求式子x+y分之5(x-y)—2(x-y)分之x+y的值
若x、y为整数,√x(√x+√y)=3√y(√x+5√y),试求2x+(√xy)+3y除以x+(√xy)+y